Question

(1+kx)(64-192x-240x^2)=0
Expand and Find the value of k in which in there is no term in x^2

Answer 1

find the product

Answer 2

the sum of the coefficients of x^2 is 0

Answer 3

the productt of what sorry i dont understand

Answer 4

product of (1+kx) and (64-192x -240x^2)

Answer 5

ok, u have not to find the whole answer . u know that u will get x^2, by multiplying -240x^2
and 1 , -192x and kx

Answer 6

so,-240 -192k=0

Answer 7

look at the terms in x^2

so its 1*(-240x^2)

and kx*(-192x)

to find the value of k... equate the terms and solve for k


\[-240x^2 = 192kx^2\]

k = -240/192

\[k =- \frac{5}{4}\]

Answer 8

cheers :)