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Tell me if my solution is correct for this one: Q: Given f(x)=cos(x^3), find \(f^{(15)}(0).\) S: The Maclaurin series of f(x) is given by \[\sum_{n=0}^{\infty} (-1)^{n+1}\frac{(x^3)^{2n}}{(2n)!}\]. The coefficient of x^15 is 0; therefore, \(\frac{f^{(15)}(0)}{15!}=0\) and consequently, \(f^{(15)}(0)=0\).
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seems legit to me, i would have just said that all the odd derivatives are in the form of \[C*x^n*\sin(x^3)\] but that works too
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