What is a "normal line"? they say to get the normal line of a parabola...
A parabola goes into a curve..is that what they mean?
I know that, I need to know what a "normal line" is
Shouldn't there be an equation with that?
Hold on that was a stupid question..and I know the answer to this...Gimme a minute.
they say "Find the equation of the normal line to the parabola y=x^2 - 5x +4 that is parallel to the line y= (1/3)x -5/3
http://answers.yahoo.com/question/index?qid=20071125140023AAebnO1 You mean this?
I read that, but it made no sense to me
Oh..okay. Well I can't find anything else. Sorry. Hope you get help Dooooom.
ok
perpendicular to tangent line
but the tangent line can be allot of places
....?
it can be at most; in 2 places ...
what is the perp slope of the parallel line?
1/3
thats the line that the normal is parallel to; we want a tangent, not a normal; so perp that slope; flip and negate
-3?
good now find the derivative of the ellipse equation that gives us a value of -3
The normal line is the line perpendicular to the slope of the curve at the point of intersection. The normal is therefore perpendicular to the tangent line
or equate it to the line: y=-3x+c ; and retrive 2 solutions for c
@ZhangYan where it intersects what?
but id go my first idea; find the points then establish the lines
so, i need to find the derivative of the parabola, right?
the equation you provided yes; I thought you said it was an ellipse :)
it is a parabola
f' = -3 is what you want to solve
how though?
sorry if i am asking stupid questions, my mind is just going blank
if you havent taken calculus yet, then derivatives wont make sense to you
if you have taken calculus, then this is the simplest of derivatives .... its a power rule
i am taking it right now, i am just really struggling with it
i am in chapter 3
\[\frac{d}{dx}x^n=nx^{n-1}\]
i know how to get derivatives with the formulas they give you
so, once you get -3, what do you do next?
the x value for f'=-3 is the x value you need to use in y to find the value if y so that you have a point to create the parallel line with. the slope of the parallel is the slope of the given: 1/3 you have a point to attach it to, so use the point slope form of a line to determine the outcome
i should used consistent letters .... the x value for y' = -3 is the same x value to use in the y= part
ok, i think i get it now...
good luck ;)
thank you for your help
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