PLEASE HELP. A manufacturer of a brand A jeans has daily production costs of c=0.2x^2-90x+10,700, where C is the total cost (in dollars) and x is the number of jeans produced. How many jeans should be produced each day in order to minimize costs? what is the minimum daily cost?
@aznbobo We want to minimize the cost. This question of maxima and minima. I'll guide you and you'll solve it. You agree with this?
yes
Ok find c'(x)
minimum daily cost would be when you produce nothing...
@aznbobo did you got my point???
@sheg We'll just find out that x=0 won't give us the lowest cost
@aznbobo Did you find c'(x)
i do not know how to do that. >.>
@ash2326 plug in x=0 and see what you get it is fixed cost that incur to the company when the company produces virtually nothing
when i plug in 0 for x i get... 10700
@aznbobo that's not right. Do you know differentiation?
now if you are talking of finding out the minimum cost by finding the total number of jeans produced so in this case we can use the Khun-Tucker condition which states that if the first derivative of any equation is equal to zero and the second derivative is positive then we can get the minimum cost @ash2326
so differentiate the given equation
@aznbobo Do you know parabolas?
Kuhn-Tucker Condition*
yes parabolas
@aznbobo you just need to differentitate the given equation with respect to x
@aznbobo how's the graph of \[c(x)=0.2x^2-90x+10700\] Does it have concavity upwards or downwards?
upwards.
on diff. you will get 0.4x - 90 = 0 again diff. wrt x 0.4 that is a positive quantity so the above equation fulfills the Kuhn-Tucker Condition so above equation i.e., 0.4x - 90 = 0 0.4x = 90 x = 225 so number of jeans produced would be 225 and by plugging in x = 225 you can calculte the minimum cost
Good you know this function is our cost function. The cost will be minimum at the vertex, can you find the vertex of this graph?
umm i think (225,275)?
How did you find it? Can you explain a little?
i graphed in on the calculator..
You know standard form of a parabola is \[y=a(x-h)^2+k^2\] Where h,k is the vertex here \[c(x)=a(x-h)^2+k^2\] We need to convert the equation in this form and we'll get the minimum cost as k and no. of jeans as h. Do you understand this?
so k is already given at 10700, right? h would be... 90?
No it's not easy, we need to convert in that form We have \[c(x)=0.2x^2-90x+10700\] We need it an a form \[c(x)=\underline{a(x-h)^2}+k^2\] Notice the underlined term here we need to have a perfect square term (x-h)^2 do you understand the difference?
yes
Great, ok let's get to work now
We have \[c(x)=0.2x^2-90x+10700\] now this can be written as \[c(x)=0.2(x^2-450x)+10700\] now we have \[x^2-450\] We need to convert this to a square term, Can you do that?
x=\[15\sqrt{2} \] & \[-15\sqrt{2} \]?
@aznbobo We need to convert this to a perfect square term \[x^2-450x \longrightarrow(x-a)^2\] Can you do it? If you can't I'll help you:)
mmm i can you help me please? :]
Ok \[x^2-450x\] Whenever you need to convert into a perfect square, add and subtract the square of half the coefficient of x here coefficient of x is 450, so half of it is 225, We'll add and subtract the square of this, so we have \[x^2-450x+225^2-225^2\] so We get \[(x-225)^2-225^2\] so We'll substitute this for x^2-450x \[x^2-450x\longrightarrow (x-225)^2-225^2\] Do you understand this?
okay
Now we have \[c(x)=0.2((x-225)^2-225^2)+10700\] It can be written as \[c(x)=0.2(x-225)^2-0.2 \times 225^2+10700\] \[c(x)=0.2(x-225)^2-0.2 \times 50625+10700\] \[c(x)=0.2(x-225)^2- 10125+10700\] Finally we get \[c(x)=0.2(x-225)^2+ 575\] So we have the form of \[c(x)=a(x-h)^2+k\] here k is the minimum cost and h is the no. of jeans for minimum cost, the vertex is h,k here it's h=225 and k=575 so no. of jeans=225 minimum cost= 575
@aznbobo Do you understand this?
@ash2326 thats what i calculated using the Kuhn_Tucker Condition
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