Question

a,b,c,d,e are 5 different intigers, a*b*c*d*e=45
then a+b+c+d+e=?

Answer 1

First, notice that if you were to choose all positive, integers, the smallest value would be \(5!=120\). Thus, we must have at least two negative integers.

Answer 2

5

Answer 3

We also can't have \(\pm2\) in our product, but we must have \(\pm3\) because 45 is odd, and divisible by 3

Answer 4

please write sollution

Answer 5

Only 1, -1, 3, -3, 5 satisfy the conditions.

Answer 6

thank you block colder

Answer 7

thanks everybody