Let A be a nonempty compact subset of R and c in R. Prove that there exists a point a in A such that |c-a|=inf{|c-x|:x∈A}.
This seems somewhat obvious to me. Since \(x\in A\), and we want to choose some \(a\in A\) for a determined \(c\), let \(B=\{|c-x| : x\in A\}\). Now look at the set \(C=\{|c-a| : a \in A\}\). This is the same set. So the infimum of \(B\) must be the same as the infimum of \(C\). So we are done.
Let d=that infimumu. For every n>1, there is \[ x_n \in A\] such that \[| c- x_n| \le d + \frac 1 n \] Since A is compact then there is a subsequnce \[ x_{n_k} \] that converges to an elemnt a in A. Hence \[ d \le | c- x_{n_k}| \le d +\frac 1{n_k} \] when \[ n_k \to \infty , \text { we have } \\ d \le | c- a| \le d \] You are done
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