If f(x) = x − 4 and g(x) = 1 over 2x − 2, find f[g(−6)].
what the... @lgbasallote, why did you tell her I could fix this? you meanie -__- :P
she asked for you >:)) hint @rebeccaskell94 evaluate g(6) first..substitute 6 to every x in g(x)
i mean substitute -6*
would the answer be -3?
@rebeccaskell94 can take it from here @kcute_face_bhunnie-_- no :)
oh wait...1 over..didnt see that lemme re-solve
wait i got it itss 9?
g(x) = \(\frac{1}{2x -2}\) right???
these are my choices 9 3 −9 −3
or is it g(x) = \(\frac{1}{2x} -2\)
1 over 2x - 2 means 1 is on top and 2x - 2 is on the bottom
Captain Obvious has arrived ;)
i know o.O im not getting an answer in the choices
Thanks for the compliment rebecca :( How friendly you are
the only one that makes sense is g(x) = \(frac{1}{2} x - 2\)
\(\frac{1}{2} x - 2\)
@rebeccaskell94 can answer it now..
Okay, yeah, that's probably it then. I'm going to go back and hide in my mouse hole and not disturb anyone else. Especially @rebeccaskell94
that's the only one that makes sense so g(-6) = (1/2)(-6) - 2 g(-6) = -3 - 2 g(-6) = -5 substitute to x of f(x) f(g(-6)) = -5 - 4 = -9 Soorry @hero....you take things personally a lot though :( Thanks @lgbasallote
hahaha fail =))) your spaces makes it confusing :p g(-6) = (1/2)(-6) - 2 g(-6) = -3 - 2 g(-6) = -5 substitute to x of f(x) f(g(-6)) = -5 - 4 = -9
I don't go around calling people captain obvious though.
close enough ;) @lgba
thanks :)
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