Question

Find area of the region cut from first quadrant by the cardroid r=1+sin theta

Answer 1

I know the limits for theta ( 0 to pi/4) but i am not sure for r. I think it is (o to 1+sin theta) but I am not sure

Answer 2

?? any help

Answer 3

\[
\int_0^{\frac \pi 2} \frac 1 2 (1+ \sin(\theta))^2 d\theta
\]

Answer 4

thanx :) I guess my brain is sleeping!

Answer 5

first quadrant is 0 to pi/2:)

Answer 6

Yes