Question

integrate 2/square roots x -1

Answer 1

\[2/\sqrt{x-1}\]

Answer 2

Use the following information to rewrite:
\[\sqrt{x}=x^{1/2}\]
\[1/x^2=x^{-2}\]

Answer 3

By inspection the result is:
\[4/3(x-1)^{3/2}+C\]
This can be checked by differentiating back to the original expression to be integrated>

Answer 4

i am sorry. it's (2/square roots x) -1

Answer 5

is the answer (4/square roots x) -1?

Answer 6

Is this it?
\[\int\limits_{}^{}(2/\sqrt{x})-1.dx\]

Answer 7

Umm whenever you integrate a constant the result will be that constant times the variable you integrated from.

In @kropot72 integral you can split it into two parts

the second part will consist of the integral of -1 which results in -1x

Answer 8

The answer is as follows:\[4\sqrt{x}-x+C\]

Answer 9

The first part you have to integrate
\[2/\sqrt{x}\]
in respect to x.

Answer 10

THANKYOU