Question

The denominator of a fraction is 2 more then the numerator. If both denominator and numerator are increased by 1 the fraction becomes 2/3. Find the original fraction

Answer 1

let x = numerator

\(\LARGE \frac{x}{x+2}\) is the fraction

\(\LARGE \frac{x+1}{x+3} = \frac{3}{4}\)

cross multiply...

4x + 4 = 3x + 9

find x

Answer 2

\(\Large \color{purple}{{x + 1 \over x + 3} = {3 \over 4}} \)

Answer 3

do you knoow the answer @Hollywood_chrissy ? you can verify with me :)

Answer 4

\(\Large \color{purple}{ 4x = 3x + 5 } \)
\(\Large \color{purple}{ 4x - 3x = 5 } \)
\(\Large \color{purple}{ x = 5 } \)

Answer 5

do not know if you noticed but I actually make an error in the question, that fraction is 2/3 nor 3/4 as I first wrote.

Answer 6

I see how you have edited the question:
\(\Large \color{purple}{ {x +1 \over x + 3} = {2 \over 3} } \)

Answer 7

\(\Large \color{purple}{ 2x + 6 = 3x + 3 } \)

Answer 8

^that

Answer 9

\(\Large \color{purple}{ -x = -3 } \)
\(\Large \color{purple}{ x = ? } \)

Answer 10

3/5
?

Answer 11

I got 3/5

Answer 12

WHUT? Oh God.

Answer 13

I yeah lol

Answer 14

and 3/5 seems to find the condition though

Answer 15

It's actually:
\(\Large \color{purple}{ -x = -3 } \)
\(\Large \color{purple}{ x = 3 } \)

Answer 16

oh oh yeah...that makes more sense

\(\huge \frac{3}{5} \leftarrow \text{final answer}\)