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A mixture contains forty ounces of glycol and water and is ten percent glycol. If the mixture is to be strengthened to twenty-five percent, how much glycol is to be added? 4 oz 8 oz 10 oz
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40 + x = y 40(.10) + x = .25y
Systems of equations Solve for x
Put equations above in a form to be solved by elimination method 4 + x = .25y -40 - x = -y Add Fractions: -36 = -.75y Divide both sides by -1: 36 = .75y Divide both sides by .75: y = 48 x = 8 So 8 oz. But you should actually try solving these yourself rather than looking for answers.
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