The binding energy of a nucleus with atomic number Z and atomic mass number
A is given by the semi-empirical mass formula
B ( Z,A) = aA - bA s 2/3  
A
A Z 2  2
- d 1/ 3 1/ 2
2
A A
Z 

where a = 15.8 MeV, b = 18.3 MeV, s = 23.2 MeV, d = 0.7 MeV and
 = (+11.2, 0, -11.2) MeV for nuclei which are (odd-odd, odd-even, even-even).
If we consider all possible isobars of mass number 216, the most stable nuclide is

Question

The binding energy of a nucleus with atomic number Z and atomic mass number
A is given by the semi-empirical mass formula
B ( Z,A) = aA - bA s 2/3  
A
A Z 2  2
- d 1/ 3 1/ 2
2
A A
Z 

where a = 15.8 MeV, b = 18.3 MeV, s = 23.2 MeV, d = 0.7 MeV and
 = (+11.2, 0, -11.2) MeV for nuclei which are (odd-odd, odd-even, even-even).
If we consider all possible isobars of mass number 216, the most stable nuclide is