Question

closed

Answer 1

i jus need the answer dude.....

Answer 2

the answer i got was 0.71 A, still am checking how i did it

Answer 3

\( y = A sin(\omega t - kx) \)
\( F = -ky \)
Potential energy = \( 1/2 ky^2\)
v = \( dy/dt\)
Kinetic Energy = \( 1/2 mv^2 \)

equate them

Answer 4

\( 1/2 k A^2 \sin^2(\omega t ) = 1/2 m(\omega\cos(\omega t))^2 \) ... sorry for earlier, there is no kx

Answer 5

thanks fellass............:D

Answer 6

plus there is A in the right hand term

Answer 7

find the value of t, from above equation ... the omega will remain same, and use that value of t to find the value of y.