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Mathematics 16 Online
OpenStudy (anonymous):

What polynomial has roots of –5, –4, and 1 ?

OpenStudy (anonymous):

(x + 5)(x + 4)(x - 1) = 0 Zero product property. Multiply out if you can't use this form.

OpenStudy (anonymous):

Roots means solutions so that means that each of these were factors bluepig is correct in the setup

OpenStudy (anonymous):

x3 – 8x2 – 11x + 20 x3 – x2 + 22x + 40 x3 + x2 – 22x – 40 x3 + 8x2 + 11x – 20

OpenStudy (maheshmeghwal9):

ya I m with blupig u can do it

OpenStudy (anonymous):

nah I really can't but ok

OpenStudy (ash2326):

@ornadios did you understand?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

you can also plug your answers in and see if they give you zero, since they would have to be solutions to the correct answer.

OpenStudy (ash2326):

We are given that the roots are -5. -4 and 1 so the factors of the polynomial are (x+5), (x+4) and (x-1) @ornadios Do you understand this?

OpenStudy (maheshmeghwal9):

if x is root and x=5 is answer then x-5 is a factor of that polynomial according to remainder theorem .did u understand.

OpenStudy (anonymous):

Yeah I think I got what ashely was saying

OpenStudy (ash2326):

@ornadios now to find the polynomial we need to find the product of these factors \[(x+5)(x+4)(x-1)\]Can you find the product @ornadios?

OpenStudy (maheshmeghwal9):

ya u can do it!go

OpenStudy (anonymous):

ok one sec

OpenStudy (ash2326):

I'm here, let me know if you get stuck anywhere

OpenStudy (anonymous):

x3 – 8x2 – 11x + 20 answer

OpenStudy (anonymous):

I think the general polynomial is \[(x+5)^m (x+4)^n (x-1)^k\]

OpenStudy (ash2326):

@ornadios check again, you should get \[x^3+8x^2+11x-20\]

OpenStudy (anonymous):

@anhkhoavo1210 Multiples of it as well.

OpenStudy (anonymous):

thank you it was one of the questions on my semester exam and I honestly did not know how to do it it thank you. Need this class to graduate on time :)

OpenStudy (ash2326):

@ornadios you're welcome:)

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