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Mathematics 57 Online
OpenStudy (anonymous):

one more 4r^2+3r-10 I've got 4r^2+8r-5r-10 so far, but don't think its right (man I hate factoring)

OpenStudy (anonymous):

(r+2) and (r-5/4)...

OpenStudy (anonymous):

how did you get that answer? need to know that information.

OpenStudy (anonymous):

i found the value of r by the quadratic formula and gave it in factor form...i too hate factorising. so here the shortcut!

OpenStudy (anonymous):

can you show me? I don't understand the quadratic formula, I'm taking basic algebra and that hasn't been covered.

OpenStudy (anonymous):

\[r={-b \pm \sqrt{b^2-4.a.c}}\div2.a\] where b iis coefficient of linear tem i.e x and a is coefficient of quadratic tem x^2 and c is the constant term

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Quadratic_equation

OpenStudy (mertsj):

|dw:1336301814008:dw| You had a very good start. Just finish it up by grouping the terms and factoring out the GCF. I will show you:

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