help me sqrt(5+2sqrt6)+sqrt(8-2sqrt5)
simplify it
\[\LARGE \sqrt{5+2\sqrt6}+\sqrt{8-2\sqrt5}\]
yes this is the problem
I can't simplify it any further...
Try rationalizing it.
i tried but how experiment x can u give me some hint
i don't think you can do a thing with the second term
Oh ...
the first one is not too bad since \[5+2\sqrt{6}=2+2\sqrt{6}+3=(\sqrt{2}+\sqrt{3})^2\] meaning \[\sqrt{5+2\sqrt{6}}=\sqrt{2}+\sqrt{3}\] maybe there is a similar trick for the second one i don't see it yet
here is the sol. that i got from bagatrix
can any1 explain me this ?
something goofy in this solution.
@anhkhoavo1210 i don't think so
sr i deleted it :D wait for 5 minutes
what is <R><r>? and i assume there is typesetting problem because i one line i see \(\sqrt{8-25}\) which must be something else, maybe \(\sqrt{8-2\sqrt{5}}\)
yes i am thinking the same for hours is this a wrong question
i think it must be \[8 - 2\sqrt 15\] :)
\[\sqrt {15}\]
i can't get it. i got \[(\sqrt{5}-1)^2=6-2\sqrt{5}\] but i am not getting it with the 8
could it be with fractions something? o.O
ok first of all that solution is wrong, you can check by a calculator
or by experimentx link
thanks for proving it false experiment atleast 1 soln is false. now what is the true result ?
the given MUST be wrong... (I think..)
so forget that solution typos and all i cannot see what to do with this
The only thing I can see is what satellite said for the first term and then for the second one: \[\sqrt{8-2\sqrt{5}}=\sqrt{2(4-\sqrt{5)}}=\sqrt{2}\sqrt{4-\sqrt{5}}\] but what good is that? None
here is the sol. that i got from bagatrix If you evaluate the answer sqrt(7)+sqrt(6) you see it does not match the original expression.
I don't think so either....:P i think i might have multiplied the numbers in bracket forgetting the squre roots :S
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