if x(cannont equal)5, what is the answer to the Expression below in Simplest form? 100-4x^/5-x
factor the numerator and then cancel
what do you mean by factor
is it 4x^2?
assuming the numerator is \(100-4x^2\), then notice that 100 and 4 are both multiples of 4, so you can factor a 4 out to get:\[100-4x^2=4(25-x^2)\]then use the following rule:\[a^2-b^2=(a+b)(a-b)\]to simplify the numerator further. you should then be able to cancel out a common term in the numerator and denominator as satellite73 suggested.
FOILS? (a+b)(a-b)?
yes - this is known as the difference of two squares
look carefully at \(25-x^2\) and see if you can re-write as the difference of two squares.
so 25 is something squared - what is that something?
5
correct, therefore:\[25-x^2=5^2-x^2\]now use the factorisation for the difference of two squares.
i.e. use:\[a^2-b^2=(a+b)(a-b)\]where for this question a=5 b=x
do you understand ZSpence?
yes ty
ok, good. so you can solve from here I assume?
yes ty
yw
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