if x(cannont equal)5, what is the answer to the Expression below in Simplest form?
100-4x^/5-x
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OpenStudy (anonymous):
factor the numerator and then cancel
OpenStudy (anonymous):
what do you mean by factor
OpenStudy (anonymous):
is it 4x^2?
OpenStudy (asnaseer):
assuming the numerator is \(100-4x^2\), then notice that 100 and 4 are both multiples of 4, so you can factor a 4 out to get:\[100-4x^2=4(25-x^2)\]then use the following rule:\[a^2-b^2=(a+b)(a-b)\]to simplify the numerator further. you should then be able to cancel out a common term in the numerator and denominator as satellite73 suggested.
OpenStudy (anonymous):
FOILS? (a+b)(a-b)?
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OpenStudy (asnaseer):
yes - this is known as the difference of two squares
OpenStudy (asnaseer):
look carefully at \(25-x^2\) and see if you can re-write as the difference of two squares.
OpenStudy (asnaseer):
so 25 is something squared - what is that something?
OpenStudy (anonymous):
5
OpenStudy (asnaseer):
correct, therefore:\[25-x^2=5^2-x^2\]now use the factorisation for the difference of two squares.
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OpenStudy (asnaseer):
i.e. use:\[a^2-b^2=(a+b)(a-b)\]where for this question a=5 b=x
OpenStudy (asnaseer):
do you understand ZSpence?
OpenStudy (anonymous):
yes ty
OpenStudy (asnaseer):
ok, good. so you can solve from here I assume?
OpenStudy (anonymous):
yes ty
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