a body is thrown vertically up with a speed of 10 m/s from the top of a wall of height 3.45m the height from which another body should be dropped simultaneously such that two bodies reach the ground in same time (g=10m/s2) explanation??
guys pls dont help
this qn was answered before
he is posting same qn again
that was a wrong answer
no it was ryt
@experimentX pls dont post an answer
aravid gave me the answer as 26m but it is not there in the option
the answer is 24.5m
calculate the time of flight!!! while going up v = u + at, u = 10, v = 0, t= find it ... let it be t1 = 1s from prev question also distance v^2 = u^2 + 2as calculate time of while falling s+3.45 = ut + 1/2 gt^2 <--- get t1 from here, u=0 here s = u(t1 + t2) + 1/2 a(t1 + t2)^2, u =0 find s using this formula,
wow superb answer experiment :P
|dw:1336313197635:dw| To visualize it propertly
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