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Mathematics 7 Online
OpenStudy (anonymous):

Let K be a non-empty compact subset of R and c in R. Prove that there exist a point "a" in K such that |c-"a"| = inf { |c-"a"| : x in K}

OpenStudy (anonymous):

you mean inf of the distance between 2 sets: {a} and R? And what is set A. Becouse you start saying K is subset of R and later A apears....

OpenStudy (anonymous):

I'm sorry. I edited the question. Sorry for my typo :(

OpenStudy (anonymous):

proof would go like this: construct the function f(c) = |c-"a"| then there are two posibilities: 1º if c=a it's trivial 2º if c distinct of a, the function is continuous on K and since K is compact it achieves there it's minimum and maximum. That's it

OpenStudy (anonymous):

I found hint but not for infimum but for supremum. It goes like this, If n in N (natural number), there exists \[a_{n} \in K\] such that \[\sup {|c-a|: a \in K } - 1/n < |c-a_{n}|\] and asks to apply Bolzano-Weierstrass Theorem.

OpenStudy (anonymous):

i gave you the proof already.

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