a long straight rope is lying on a floor is pulled along its length with uniform acceleration along its lenght if the velocities of the front and back ends of the rope when it passes through a particular point on the floor are 2m/s and 4m/s respectively the velocity of the midpoint of the rope when it passes through the same point is?

Question

experimentx · Answer

$ v_1 = 4, u = 2 $
$ (v_1)^2 = u^2 + 2as $
$ (v_2)^2 = u^2 + 2a(s/2) $
Find $ v_2 $ !!!

anonymous · Answer

did nt understand (v2)2=u2+2a(s/2)

experimentx · Answer

the distance travelled by midpoint will be half the distance travelled by the rear end.

anonymous · Answer

ok now i get it thanxxx