A quadrilateral ABCD has four right angles. The diagonals bisect each other. Based on the given properties of the quadrilateral ABCD, which of these is a valid conclusion? A.) Quadrilateral ABCD must be a square. B.) Quadrilateral ABCD must be a rhombus. C.) Quadrilateral ABCD must be a square or a rectangle. D.) Quadrilateral ABCD must be a rectangle or a rhombus.
Robb - how do you think it ?
Let's eliminate them: Based on the first statement, we can say that it is a square or rectangle. Based on the second statement, we can again say that it is a square or a rectangle. So, we say that Squares and Rectangles make the statements true =))
So, option C. is correct.
ok thank you guys :)
Quadrilateral ABCD must be a square or a rectangle. For square, diagonals bisect each other, and there are 4 right angles. For rhombus, diagonals bisect each other. But there is no right angle. (or may not have right angles) For rectangle, diagonals bisect each other, and there are 4 right angles. From here you can get the answer. Sorry ... it's too late... :(
To be a square the diagonals have to bisect each other at right angles (they are not congruent however)
For a rectangle the diagonals just bisect each other and they are congruent.
so are you saying its not C. ?
@Callisto
@_@ I guess it's C ?!
ok ill let you know if it is
It is. The diagonals in both figures bisect each other.
It is indeed C.
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