Question

three points a , b, c are on a straight line such that ab=bc .a particle moving with uniform acceleration a and c with speeds of 6m/s and 8m/s another particle moving with uniform acceleration passes a and b with speeds of 12m/s and 14m/s it t1 and t2 are taken by the particle to cross ab t/t2 is??

Answer 1

can you clarify the last statement??

Answer 2

u have find t1/t2 (ratio)

Answer 3

"it t1 and t2 are taken by the particle to cross ab t/t2 is??" ???

Answer 4

sorry it is t1/t2 (ratio)

Answer 5

same as before, use v=u+at

Answer 6

Oo ... something is wrong!!!

Answer 7

can u give the full equation

Answer 8

is AB for both particles??

Answer 9

yes

Answer 10

speed of particle 1 at b = (6+8)/2 = 7

now use v = u + at for both ... and take ratios!!

Answer 11

can u give the solved answer plzzzz

Answer 12

\( 8 = 7 + at_1 \)
\( 14 = 12 + at_2 \)

Answer 13

thnxxxxx

Answer 14

didi it work out?? I still have many doubts!!!

Answer 15

s ur answer is correct

Answer 16

well ... don't blame if it gets incorrect again ... LOL