Question

Write the equation in polar coordinates:
x^2+y^2=4

Answer 1

@satellite73 here

Answer 2

@saifoo.khan here

Answer 3

hi :D

Answer 4

circle with center (0,0) radius fixed at 2 right?

Answer 5

radius is right

Answer 6

so \(\theta\) can be anything but \(r=2\)

Answer 7

the answer just radius, nothing else, i dont understand lol o_0

Answer 8

so x^2 and y^2 = 0,0 ?

Answer 9

yes you are fixing the radius at \(r=2\) whereas \(\theta\) can take on any value

Answer 10

equation is \(r=2\)

Answer 11

so what if it was x^2+y^2=9 then it would be (0,0) r=3 ?

Answer 12

think by analogy to the equation for a horizontal line in rectangular (regular old) coordinates. say at \(y=2\) then we just write \(y=2\) without the \(x\) because \(x\)can be anything, \(y\) does not depend on \(x\), and \(y\) is a fixed number
just like in your example above, \(\theta\) can take on any value, but \(r=2\) a fixed number

Answer 13

yes you are right