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Please explain...
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its simply, really
\[6\div r ^{2}-1 -1\div2=1\div r-1\]
lcd=\[(r ^{2}-1)(r+1)(2)?\]
the last term is suppose to be 1/r+1
is this your question?:\[\frac{6}{r^2-1}-\frac{1}{2}=\frac{1}{r+1}\]
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yes
use the fact that:\[r^2-1=(r+1)(r-1)\]
okay r^2-1 = (r+1)(r-1) make all the denominators match
and then multiply both sides by (r+1). that should simplify the expression.
I need to leave now - but hopefully there are plenty of people here that can assist you...
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