Question

Divide

sqrt 180x^3/sqrt 10x^-7

Answer 1

\[\LARGE \frac{\sqrt{180x^3}}{\sqrt{10x^{-7 }}}\]

hint... split 180 into prime numbers...

Answer 2

I got 3sqrt2/2x^2 which was incoorect

Answer 3

\[\LARGE \frac{\sqrt{180}\cdot \sqrt{x^2}}{\sqrt{10}\cdot \sqrt{x^{-7} }}=\]
\[\LARGE \frac{\sqrt{90\cdot 2 }}{\sqrt{10} } \cdot \frac{ \sqrt{x^2}}{ \sqrt{x^{-7}}}=\]
\[\LARGE \frac{\sqrt{45\cdot 2 \cdot 2 }}{\sqrt{10} } \cdot \frac{ x^{1/2} }{ x^{-\frac72 }} =\]
\[\LARGE \frac{\sqrt{45\cdot 2^2 }}{\sqrt{10} } \cdot \left(x\right)^{\frac12-(-\frac72 )} =\]
go on...

Answer 4

Sqrt(x^3) is the same as x^(3/2) and Sqrt(x^-7) is equal to x^(-7/2). When dividing the x^(3/2) by x^(-7/2) we subtract the exponents 3/2 - (-7/2). Kreshnik you made an error it's the Sqrt(x^3) not of x^2 but the rest is ok.

Answer 5

ahh sorry... @Kaden thanks for pointing that out :) ... @Courtney.soden just fix that and go on ;)

Answer 6

lol and that wouldn't be 1/2 that would be 2/2 hahahah I'm so dumb lol

Answer 7

No probs, I didn't even see the fact that I could post proper equations until after I posted.

Answer 8

seems like she left. and Closed this. I'm out. Take care. :)

Answer 9

You too, thanks for medal.