Question

simplify and state excluded values. 3b^2+13b+4/b+4

Answer 1

you have a qudratic in the numerator. factor it and see what you get

Answer 2

u cant factor 13

Answer 3

there is a method called "ac" which works for some quadratics. do you know it?

Answer 4

no

Answer 5

ok. you multiply a times c. In this case that would be 3 times 4. That produces 12.
Now you find factors of 12 which add up to b=13.
Can you do that?

Answer 6

12 and 1

Answer 7

correct. so set up the equation as follows:\[3b ^{2}+12b+b+4\]

Answer 8

12 and 1 for the 13b

Answer 9

now factor by grouping
\[3b(b+4)+(b+4)=(3b+1)(b+4)\]

Answer 10

now insert this into the entire fraction
\[(3b+1)(b+4)/(b+4)\]
and what do oyu get?

Answer 11

3b+1??

Answer 12

really good. Sorry to make it so long but if you don't see and undrstand all of the steps you'll never get it.

By the way, b=-4 is an excluded value because if you look at the original equation -4 causes division by 0 which is undefined

Answer 13

ok?

Answer 14

ok thanks so much

Answer 15

good night

Answer 16

you to