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consider this equilibrium: 2 NO2(g)⇄ N2O4(g) 2.00 moles of NO2 and1.60 moles of N2O4 are present in a 4.00 L flask at equilibrium at 20oC. Calculate the Keq at 20oC.
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20oC=20 celsius
hello? o.0
just a moment im calculating
here it is, im not sure if its correct but you try to calculate it too: first you calculate pressure of each components by equation p=nRT/V (dont forget to transfer temperature from °C -> K and volume from dm3 -> m3) then its simple just use next: Kp = p(N2O4)/[p(NO2)]^2 and you should get 1,28 *10^-6
thx
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