Find the annual percent increase or decrease that y=0.35(2.3)^x models. if possible, show work.
Where x is time in years?
yes.
Well. If you have an exponential function like: \[y = a(b)^x\] a will be your starting value, and every time x increases by one, y will be multiplied by the amount b. So here's a simple example of that: \[y=10(2)^x\] When x=0, y = 10. 10 is the starting value. Every time x goes up by one, y will be multiplied by 2, or doubled. So x=1 gives y = 20 x=2 gives y =40 x=3 gives y =80 x=4 gives y = 160 x=5 gives y = 320 Seeing the pattern? So that means that, for this function, y will always be twice as large as last years y. As a percent, that would be 200% Try to figure out what that means for your problem, and ask me any question you have.
agree with above ^^ Note: it asks for percent increase/decrease though so you need to subtract 100% essentially think of it as y = (1+p)^x where p is rate of increase
Thanks!
Oh right right. My example isn't a 200% increase. It's a 100% increase. Good catch, buddy.
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