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Mathematics 20 Online
OpenStudy (anonymous):

See attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

Find the standard equation of the circle.

Directrix (directrix):

@sakigirl --> What are the coordinates of the center of the circle? Count on the diagram.

OpenStudy (anonymous):

C: (2, 2) r: 4

Directrix (directrix):

@sakigirl --> I think you counted on number 1 but I'm not sure. If so, I got (2,4) and r = 4. I was thrown off by each unit representing 2 and not the "usual" one.

OpenStudy (anonymous):

I'm pretty sure the center's (2,2)

Directrix (directrix):

One number 2?

OpenStudy (anonymous):

OH, gosh, I feel dumb. You're right, totally sorry about that.

Directrix (directrix):

I feel crazy because each block on number 1 is 2 units but on number 2, each block is 1 unit. No, worries. Do you remember the standard form equation of a circle? We are doing problem NUMBER two - right? :)

OpenStudy (anonymous):

Yes. And isn't it (x-h)^2+(y-k)^2=r^2?

OpenStudy (anonymous):

But for the center of the circle for number 2, I see (-3, 2)

Directrix (directrix):

Yes on the formula. On number 2--> C: (-3,2) and r: 2. Do you agree?

OpenStudy (anonymous):

Yes.

Directrix (directrix):

You crank out the equation for number two. I'll do the same. Then, we'll compare answers.

OpenStudy (anonymous):

(x+3)^3+(y-2)^2=4

Directrix (directrix):

( x - (-3) )^2 + (y - (2))^2 = 2^2 (x + 3) ^2 + ( y - 2) ^2 = 4

OpenStudy (anonymous):

Oops, I meant to the squared of 2.

Directrix (directrix):

Your answer is correct. 2^2 = 4

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