Question

x^2-1/x^2-x-2 - x-1/x-2

Answer 1

Assuming your problem is to simplify this:\[\frac{x^2-1}{x^2-x-2} - \frac{x-1}{x-2}\] You want to look at factoring and getting a common denominator for them.

Answer 2

ok

Answer 3

Do you know how to add and subtract fractions?

Answer 4

no

Answer 5

okay well say you have 1/2 + 1/4 you would need to muliply each denominator by the opposite fractions numerator and then multiply both the denominator together to get your new base here you are doing the same thing except with x's and such

Answer 6

know what I mean? once you do that you can factor

Answer 7

oh and the new numerators you get are added together over top of your new denominator well in this case subtracted.

Answer 8

((x^2-1(x-2))-(x-1(x^2-x-2)))/((x-2)(x^2-x-2)) this is what you should get and then you would simplify and then factor I think

Answer 9

so if it looked like this a/b - c/d you would end up with (ad-cb)/(bd) do you see what I did?

Answer 10

ya

Answer 11

(x^3-2x-x+2 -x^3+x^2+2x+x^2-x-2)/(x^3-x^2-2x-2x^2+2x+4) I think you should get this when you distribute everything