Question

Find: Limit of

Answer 1

factor the denominator to start

Answer 2

\[\lim_{x \rightarrow -3}{x+3\over x ^{2}-x-12}\]

Answer 3

\[x+1\over x ^{2}-x-4\] @ChukRock like this?

Answer 4

He meant to factor \(x^2-x-4\)

Answer 5

no like this \[(x+3)/(x+3)(x-4)\]

Answer 6

that way you can cancel the (x+3) in both numerator and denominator

Answer 7

oh okay yea its gonna be \[-1\over 7\]

Answer 8

-4+3 = -1
-4*3 = -12

x^2 + 3x -4x -12
x(x+3)-4(x+3)
(x-4)(x+3)

Answer 9

@ChukRock 's way is the more elegant, in my opinion. Another way of doing it is to divide everything by x^2.

Answer 10

@bmp good seeing you again! oh okay thanks for the tip

Answer 11

thanks @zepp I appreciate the help

Answer 12

No problem, and same to you :-)

Answer 13

You are welcome :)