Question

Solve:

Answer 1

\[x \left| x-4 \right|+a=0\]

Answer 2

what have you tried so far?

Answer 3

i have done \[x-4=\pm (-a/x)\]

Answer 4

2-sqrt(4-a), sqrt(4-a)+2, 2-sqrt(a+4), sqrt(a+4)+2

Answer 5

How?

Answer 6

please tell

Answer 7

it is quadratic

Answer 8

k!

Answer 9

(-b±sqrt(b^2-4ac))/2a

Answer 10

no wait it can be done much easier

Answer 11

But please tell how can I make original eq. into quadratic

Answer 12

i think it can be \[(x-4)^2x^2=(-a)^2\]

Answer 13

k!

Answer 14

ok

x−4=±(−a/x)

x(x-4) = ±(−a)

x^2-4x = ±(−a)

x^2-4x±a = 0

using the formula

x = (4±sqrt(16±4a))/2

x = (4±sqrt(4(4±a)))/2

x = (4±2sqrt(4±a))/2

x = 2±sqrt(4±a)

Answer 15

there are 4 possible solutions

Answer 16

oh thanx a lot! I got it now.