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What is the integral of (x^2+1/ x) dx from 1 to e?
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\[\int\limits_{1}^{e} (x^2+1) / x\]
split it into 2 fractions x^2/x = x
integral of 1/x is ln(x)
so it becomes x^2/2 + ln(x)
correct, then evaluate F(e) -F(1) where F = x^2/2 +ln(x)
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i get (e^2+1/2) - (1/2 - 0) . Did i evaluate correctly?
the first part should be e^2/2 + 1
Oh yeah thats corect. So when combined is (e^2 - 1 / 2)
correction that subtraction should be addition
so the final answer is (e^2+1/2)
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yes ...if that is (e^2 +1)/2
right thats what i have. Thank you so much for explaining. =) Im so bad with integrals.
no problem
Do u mind helping me with another problem. im posting it now.
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