a body is thrown vertically up with a speed of 10 m/s from the top of a wall of height 3.45m the height from which another body should be dropped simultaneously such that two bodies reach the ground in same time (g=10m/s2)

Question

dumbcow · Answer

using g = 10
solve the quadratic
$$-5t^{2}+10t+3.45 = 0$$
t = 2.3
Then use
$$-5t^{2}+h = 0$$
plug in value for t and solve for h

h = 26.45

anonymous · Answer

ha(t) = (g*t^2)/2 + va*t + ha

g = -10
va = 10
ha = 3.45
t = ?

0 = -5t^2 + 10*t + 3.45

t = 2.3



hb(t) = (gt^2)/2 + vb*t + hb

g = -10
vb = 0
hb = ?
t = 2.3

0 = -5(2.3^2) + hb

hb = (aprox)26.45m

vincent-lyon.fr · Answer

@shameer : why do you post this question THREE TIMES? It was already widely discussed and solved in the link below. You are wasting people's time, working on and answering an already solved problem. http://openstudy.com/users/shameer1#/updates/4fa62981e4b029e9dc35e6e7

anonymous · Answer

the answer is 24.5m can anybody solve for it

vincent-lyon.fr · Answer

We proved earlier that this answer is NOT correct! Are you not convinced?

anonymous · Answer

nobody got this aanswer correct

vincent-lyon.fr · Answer

People who write books and problems sometimes do mistakes too, you know!
Stop worrying with this problem and go on! Either something is wrong in the way it is written, or there was a mistake in the answer provided.

anonymous · Answer

i think u r right  thanxxxx

vincent-lyon.fr · Answer

Even the grammar in this problem sucks.

anonymous · Answer

and sorry toooo!!

vincent-lyon.fr · Answer

ok! :) Trust OS for wise answers!