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Mathematics 8 Online
OpenStudy (anonymous):

A type of weeping cherry tree will flower when it is taller than140 cm but no more than 200 cm. If a tree is purchased when it is 50 cm tall and it grows 20 cm each year, during what time period will the tree flower?

OpenStudy (lgbasallote):

it will flower when the tree is greater than or equal to 140 cm...it grows 20 cm a year let x = no. of years how would you set up the equation?

OpenStudy (anonymous):

...wouldn't it be ....140 <20x? o . o Then at that point you'd divide both sides by 20 and get 70?

OpenStudy (anonymous):

...I'm utterly hopeless with Algebra, even the basic stuff. ~ _ ~'' The rest of the question asks for a set, or rather the lower and upper limits.

OpenStudy (lgbasallote):

why 140 < 20x? may i just ask?

OpenStudy (anonymous):

Because I haven't been to sleep and it's almost 4am and I have school in about 2 hours o - o'' I suck at this sort of thing in my waking hours ,so now isn't any better. The only reason I'm forcing myself awake is because I was told at the last minute ( graduation is in less than 5 weeks ) that I needed to make up half of an Algebra credit from my freshman year of high school e _ e''

OpenStudy (lgbasallote):

i dont think any of that explained the 140 < 20x sorry...

OpenStudy (anonymous):

The answer would be between 5 and 8 years, wouldn't it? o . o

OpenStudy (lgbasallote):

hmm you'll have to use algebra too be sure

OpenStudy (anonymous):

140=20x+50 solve for x, 200=20x+50 solve for x. You'll get 4.5 years and 7.5 years so I think you're estimate is correct if you must round up a year good job.

OpenStudy (anonymous):

I'm really no good at this > _ <'' Thanks for the help <3

OpenStudy (lgbasallote):

not equal @marvin.cling 140 \(<\) 20x + 50 \(\le\) 200

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