Question

ln [(3+4x^2)^1/2]
find the domain and derivative

Answer 1

\[\large y = \ln (3+4x^2)^\frac {1}{2}\]
\[\large y' = \frac {[(3+4x^2)^\frac {1}{2}]'}{(3+4x^2)^\frac {1}{2}}\]
\[\large y' = \frac {\frac {1}{2}(3+4x^2)^{-1/2}(8x)}{(3+4x^2)^\frac {1}{2}}\]
simplify the rest...

Answer 2

I see where I messed up, thanks!

Answer 3

yw...
btw, do you know the domain?

Answer 4

negative to positive infinity right?

Answer 5

correct... all reals.. :)
good work.