Question

INTEGRALS

Answer 1

\[x(\sqrt(2x+1))dx\]

Answer 2

let u = 2x+1
du = 2dx

Answer 3

i then get x(u)^(1/2)(1/4du) and then im stuck

Answer 4

i have no idea how to do that, we have not and will not have gotten to integrating by parts this semester

Answer 5

Let\[\int x\sqrt{2x+1}\text{ }dx.\]Set \(u=2x+1\). Then \(du=2dx\), and\[\frac{1}{4}\int (u-1)\sqrt{u}\text{ }du\implies\frac{1}{4}\int\sqrt{u^3}\text{ }du-\frac{1}{4}\int\sqrt{u}\text{ }du\text{ }\dots\]