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Chemistry 7 Online
OpenStudy (anonymous):

COMBUSTION OF HEAT can i get help on number 3 please?

OpenStudy (anonymous):

number 3

OpenStudy (4n1m0s1ty):

Just rearrange and solve for C, you have delta H = 3226 kJ/mol, delta T =0.009 C, and n = 8.27 mol. C = deltaH*n/deltaT = ((3226 kJ/mol)*(8.27 mol))/0.009 C = ??? kJ/C

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