Find the slope of a line passing through (6, 7) and (2, 9) A. negative one-half B. one-fourth C. -2 D. -4
\[\text{Slope of a line passing through points } (x_1,y_1) \ and (x_2,y_2) \text{is given by}\]\[\large Slope= \frac{y_2-y_1}{x_2-x_1}\]
Now can you substitute the values and try it ?
I'm really confused on this. /:
Its ok ,i can help you
line is passing through (6, 7) and (2, 9) here x1=6 y1=7 x2=2 y2=9 Now can you substitute it in the formula and find slope?
So I think my answer would be C. -2.
how did you get that ? can you show me?
I don't know how to solve this... so I'm just assuming so.
dont assume What's the formula for slope?
y^2-y^1 over x^2-x^1
\[y ^{2}-y ^{1} \over x ^{2}-x ^{1}\]
Its not squared ...
(6, 7) is (x1,y1) and (2, 9) is (x2,y2) Ok ?
Oh oops! My bad!! Sorry about that.
Ok now what's x1 ,x2 ,y1 & y2 ?
Idk
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