How do I factor a^4-4a^3-2a^2+12a+9
it looks binomial in structure
Okay...
but thats not always the case
start with the rational root thrm
if that doesnt get us someplace, then it gets messy
I've been trying to pair things up and then take out common factors but it's not working
factors of last term +- ---------------- factors of first term this would give us a pool of options to narrow down
1,3,9,-1,-3,-9 try using these as roots to divide out
or ... if f(1,3,9,-1,-3,-9) produces a zero, its a root
a^4 - 4a^3 - 2a^2 + 12a + 9 1 | 1 | 0 2 or 0 positive roots a^4 + 4a^3 - 2a^2 - 12a + 9 1 | 1 | 0 2 or 0 negative roots
It's all gravy I figured it out , thanks
cool :)
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