Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is the coefficient of kinetic friction?

Question

ujjwal · Answer

$$F=mu N$$

anonymous · Answer

Answer Choices ; 
A. 0.01 
B.0.20
C. 0.38
D. 0.48

anonymous · Answer

WHICH 1?

anonymous · Answer

why don't you solve with the formula and find out?

anonymous · Answer

I COULDNT READ IT WHAT IS IT?
F= WHAT?

ujjwal · Answer

F is force applied, mu is coeffitient of kinetic friction and N is normal force..

anonymous · Answer

i dont gave that on my fourmla chart:/

anonymous · Answer

you push the book with 19.5 newtons to the right, friction holds the book backwards, therefore;

19.5 - ForceFriction = 0
19.5 = Force Friction (Force of friction = (coefficient of friction)(normal force)

we know the normal force 51.7 newtons, therefore

19.5 = (coefficient of friction)(51.7 newtons)
19.5/51.7 = coefficient of friction

anonymous · Answer

well its cuz this is a 5 question quiz and i have to get 4 or 5 right to pass..and my teacher said i dont have to pass as long as i finish my work then she will pass me cause im not going to summer skool she let us google the answers 2 but sometimes they dont work lol:/

anonymous · Answer

Risky ; So we mutiply those 2 numbers? 19.5 times 51.7 or we divide?

anonymous · Answer

divide:)

anonymous · Answer

Mkay hunn hold up lol

anonymous · Answer

i got 0.37

anonymous · Answer

is thatt right?

anonymous · Answer

if you can divide correctly it should be :p

anonymous · Answer

i got it right lol:) thank you boo

anonymous · Answer

can you help me more or no?