Question

use the sum or difference formula for tangents to find the exact value of cot (-5π/12)

Answer 1

i guess you are supposed to recognize that \(-\frac{5\pi}{12}\)is half of \(-\frac{5\pi}{6}\) and use the "half angle" formula for tangent, then take the reciprocal

Answer 2

Using the formula: (tan A − tan B) / (1 + tan A tan B)
*Note* 3pi/12-8pi/12= -5pi/12

1+sqr(2)/(1+1*sqr(2))

simplify and u have your answer

Answer 3

agree with ^^
except tan(2pi/3) = -sqrt(3) Not -sqrt(2)

Answer 4

yes sorry i apologize


1+sqr(3)/(1+1*sqr(3))

Answer 5

which equals 1.634

Answer 6

something is off there
\[\tan(\frac{\pi}{4} -\frac{2\pi}{3}) = \frac{\tan(\frac{\pi}{4}) -\tan(\frac{2\pi}{3})}{1+\tan(\frac{\pi}{4})\tan(\frac{2\pi}{3})} = \frac{1+\sqrt{3}}{1-\sqrt{3}}\]
then take reciprocal to get cot

Answer 7

don't forget to rationalize the denominator