Help please: Point P moves with angular velocity "w" on a circle of radius "r". In each case, find the distance "s" traveled by the point in time "t" w= 10rad/sec, r = 6 ft, t = 2 min
v= w*r
\[2 \min \times\frac{10rad}{1 \sec}\times\frac{1revolution}{2pi rad}\times\frac{12pi feet}{1 revolution}\times\frac{60 \sec}{1 \min}=7200 feet\]
ok hold on let me think ^^!
is there an easier way to do this?
in my book, the angular velocity formula is: w=theta/t (where theta measured in radians)
can i use that formula some how ?
@Mertsj hi ?
Yes you can. I was trying to help you understand why it is what it is.
They gave you the angular velocity when they said w=10 rad/sec
i think i got the answer but im not sure
just plug it in the formulas i guess, to find v then use v=rw which is 6x10=60
then when u got v=60 just multiply that with t=2, 60x2=120
i dont know, cuz there's a similar problem to that in here, but the t is in second
The linear velocity can be found by the formula linear velocity = angular velocity times radius. In your case linear velocity = 10 rad/sec times 6 feet. That would be 60 feet per second. in two minutes, there are 120 seconds so multiply that by 60 feet per second. 60(120)=7200 feet
oh 60x120
so if t=1 minute then i just take 60(60) ?
You have to pay attention to the units, yes. If you have feet in 1 second and you want feet in 1 minute you would multiply by 60
oh i see.. cool :D thanks Mertsj
yw
one more thing..
You must be watching "The Five" That's what they always say at the end of their show.
lol ^^!
Is there anyway that i can graph this using the calculator? y=cos1/3x ?
in radian btw
I can on mine. Doesn't yours have a setting for radians or degrees?
I have TI-84 and yes it does have radian and degrees
Then enter it like y =cos ((1/3)x)
Otherwise the calculator might think it is 1 over 3x
oh nice
Did it work?
but it look different from the answer
how do i zoom in to fit 1cycle only ?
Define the domain
it look totally different >.<
btw the period of the graph tells when the graph stop/end right ?
The graph goes on and on forever but the period covers 1 complete cycle. In the case of y = cos(1/3)x, the period is 6 pi or 1080 degrees
So you could set your domain from -3pi to 3 pi or from 0 to 6 pi. That would give you a complete cycle.
for all the graphs ? or just this one ?
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