Find B D. B: {−2, −1, 1, 4, 7, 12} D: {numbers divisible by 3 from 1 to 15}
Is this "Find B D" meant to be "Find B intersect D" or perhaps "Find B union D"?
sorry about that it's B union D...
@Directrix
The union will be all the elements in set B together with all the elements in set D. If there is a duplicate, just write it one time in the union.
So, I would start with all the elements in set B and then see what is in set D that is different and add it to the list of elements for the union.
@Jezz007 --> What numbers come from this: {numbers divisible by 3 from 1 to 15}. List them here. Then, I'll get the elements from B, and we'll put them together.
1 and 3 ??
One is divisible by 3 (answer of 1/3) but in this context, divisible by 3 means multiples of 3. Sorry - I forgot to say that before you started working. So in set D, 3 is divisible by 3 because the quotient is 1. Is 4 divisible by 3? No Is 5 a multiple of 3? No Is 6 a multiple of 3? Yes because 6/3 = 2 with no remainder. So far, we have 3 and 6. What are the others after 6? Post here. When we get them all, we'll put them in ascending order (smallest to largest) for the union.
You are working in just set D. Don't look at set B right now.
So far, we have 3 and 6 from set D. There are 3 others. Do you know how to find them?
dividing them right?
9, 12, and 15?
@Directrix
Right.
From D, we have 3, 6, 9, 12, and 15. From B, we have −2, −1, 1, 4, 7, 12. Agree?
yup
B U D = { -2, -1 , 1, 3 , 4, 6, 7, 9, 12, 15 } Check -> we don't want to leave out anything.
its good
Okay. I was just thinking that the intersection of B and D would just be the number 12. Alrighty, then.
thanks buddy :)
Glad to help.
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