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OpenStudy (lgbasallote):
hint: \(\large (b-a) = -(a-b)\)
OpenStudy (mathhelp346):
what formula is that?
OpenStudy (lgbasallote):
it's not really a formula...it's a way of manipulation see.. if you distribute \(-(a-b) = -a + b = b-a\)
see?
OpenStudy (mathhelp346):
??
OpenStudy (lgbasallote):
i distributed the negative signs... \(-(a-b) = -(a) - (-b) = -a + b = b -a \quad \text{(according to commutative property)}\)
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OpenStudy (mathhelp346):
what formula is -(a-b)??
OpenStudy (lgbasallote):
it is not a formula...i factored out -1 from (b-a)
OpenStudy (lgbasallote):
do you get it?
OpenStudy (mathhelp346):
not really
OpenStudy (lgbasallote):
hmm how should i explain this...like i said i factored out -1...let's go with that explanation...in factoring you divide each factor by the value your factoring right? for example when you factor out x from 2x^2 + x it's \(\large x(\frac{2x^\cancel{2}}{\cancel{x}} + \frac{\cancel{x}}{\cancel{x}}) = x(2x +1)\) do you agree with me on that one?
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OpenStudy (mathhelp346):
yea
OpenStudy (lgbasallote):
so if i factor out -1 from (b-a)
\(-1(\frac{b}{-1}) - \frac{a}{-1} = -1[-b - (-a) ]= -1(-b + a)\)
agree?
OpenStudy (mathhelp346):
yea
OpenStudy (lgbasallote):
and -b + a according to commutative property is also a - b right?
OpenStudy (mathhelp346):
but where did (b-a) come from
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OpenStudy (mathhelp346):
is that a formula
OpenStudy (lgbasallote):
it was an example :)
OpenStudy (mathhelp346):
ok
OpenStudy (lgbasallote):
and for simplicity sake yeah let's say it's a formula \((b-a) = -(a-b)\)
so can you solve your problem now?