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Mathematics 25 Online
OpenStudy (anonymous):

how do i derive 3x*sqr(x^2+6)+4 shoulld i simplify this first?

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

you could write out the square root as an exponential so your expression will be: 3x* (x^2+6)^(1/2) + 4

OpenStudy (anonymous):

makes using the power rule easier..

OpenStudy (anonymous):

yes i have done this but after the product rule i get some long value which i dont know how to simplify

OpenStudy (anonymous):

what do you have?

OpenStudy (anonymous):

let me type it

OpenStudy (anonymous):

doo di doo di dooo... :)

OpenStudy (anonymous):

\[3x\]\[3x \times1/2(x^2+6)^-1/2 \times 2x +(x^2+6)^1/2 \times3\]

OpenStudy (anonymous):

its the bottom line i need to simplify

OpenStudy (anonymous):

hmm.. can't tell what are exponents and what aren't... this is what I got...

OpenStudy (anonymous):

exponents are after parenthases

OpenStudy (anonymous):

|dw:1336438372316:dw|

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