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Prove that (sectheta)(csctheta)(cottheta)=csc^2theta
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csc = 1/sin sec = 1/cos cot = 1/tan
tan = sin/cos thus cot = cos/sin
using these proofs you can easily break this up and solve it using basic algebra
\[LHS = sec\theta csc\theta cot \theta = sec\theta csc\theta \frac{cos\theta}{sin\theta}\]\[ = sec\theta csc\theta cos\theta csc\theta = csc^2\theta = RHS\]
remember cot = cos/sin \[\frac{1}{\cos(\theta)}\times \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}\] this its solution is \[\frac{1}{\sin(\theta)\times \sin(\theta)} = \frac{1}{sin^2(theta)}=csc^2(theta)\]
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