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f(x)= x^2 - 3 what is the range if the domain is: [-2 < x < 5]
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not necessarily
Range = f (-2) < y< f (5)
in fact for sure not. this is a parabola that opens up. its miminum value is at the vertex when \(x=0\) you get \(y=-3\) which is the minimum value of the function globally and also on the interval \([2,5]\)
make that the interval \([-2,5]\)
max is at whichever is larger, \(f(-2)\) or \(f(5)\) i think you will find that \(f(5)\) is the larger values since it is further way from 0 than -2 is
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[-3,21)
|dw:1336453723011:dw|
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