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Mathematics 8 Online
OpenStudy (anonymous):

f(x)= x^2 - 3 what is the range if the domain is: [-2 < x < 5]

OpenStudy (anonymous):

not necessarily

OpenStudy (anonymous):

Range = f (-2) < y< f (5)

OpenStudy (anonymous):

in fact for sure not. this is a parabola that opens up. its miminum value is at the vertex when \(x=0\) you get \(y=-3\) which is the minimum value of the function globally and also on the interval \([2,5]\)

OpenStudy (anonymous):

make that the interval \([-2,5]\)

OpenStudy (anonymous):

max is at whichever is larger, \(f(-2)\) or \(f(5)\) i think you will find that \(f(5)\) is the larger values since it is further way from 0 than -2 is

OpenStudy (anonymous):

[-3,21)

OpenStudy (anonymous):

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