the square root of "x+7" +5=x please solve step by step. Thanks

Question

anonymous · Answer

$$\sqrt{x+7}+5=x$$

campbell_st · Answer

$$\sqrt{x+7} + 5 = x$$

square every term 

$$x + 7 + 25 = x^2$$

rewriting 

$$x^2 - x -32 = 0$$

campbell_st · Answer

solve the quadratic by GQF

anonymous · Answer

dont you have to isolate the radical first??

campbell_st · Answer

you are solving for x... lots of ways of doing it

anonymous · Answer

i thought i subtract 5 from both sides then square each side.

anonymous · Answer

$$\begin{align}
\sqrt{x+7}+5&=x\
\sqrt{x+7}&=x-5\
x+7&=(x-5)^2\
x+7&=x^2-10x+25\
0&=x^2-11x+18\
0&=(x-9)(x-2)\
x&=9,2 
\end{align}$$

anonymous · Answer

Campbell, you squared incorrectly. You can't just square the 5, if you leave the 5 on the other side you have to square it as a binomial.

anonymous · Answer

Thanks!!

campbell_st · Answer

your suggestion 

$$\sqrt{x+7}=x-5$$

$$x + 7 = x^2 - 10x + 25$$

lgbasallote · Answer

$(\sqrt{x-7} + 5)^2$ is not squaring each term @campbell_st :D

anonymous · Answer

nbouscal can u help me with 1 more?

anonymous · Answer

Close this question and start a new one if you have another question :)

anonymous · Answer

okay dont wanna lose you lol.

anonymous · Answer

I'm not goin' anywhere :P