f(x)=4x-3 and g(x)=x^2+1 find (fg)(x) and find and simplify g(x+h)-g(x)
That's \((fg)(x)\), not \((f \circ g)(x)\), right? If so, you just multiply, so \((fg)(x)=(4x-3)(x^2+1)\). As for the second part, plug in x+h for x in g(x), then subtract g(x).
its the second one...i thought they were the same...
Nope, two different things. \((f\circ g)(x)\) is the composition of the functions, also can be written as \(f(g(x))\). So, you plug g(x) in for the x in f(x).
so it should be 4x^2+1
When you substitute it in, don't forget to put parentheses around it. Also, don't forget the -3 :)
thanks! last quesion where do i get the h for the second part
You just use x+h, you don't need h to actually be anything. So just put (x+h) in instead of x, and then simplify it
Join our real-time social learning platform and learn together with your friends!