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Mathematics 16 Online
OpenStudy (anonymous):

f(x)=4x-3 and g(x)=x^2+1 find (fg)(x) and find and simplify g(x+h)-g(x)

OpenStudy (anonymous):

That's \((fg)(x)\), not \((f \circ g)(x)\), right? If so, you just multiply, so \((fg)(x)=(4x-3)(x^2+1)\). As for the second part, plug in x+h for x in g(x), then subtract g(x).

OpenStudy (anonymous):

its the second one...i thought they were the same...

OpenStudy (anonymous):

Nope, two different things. \((f\circ g)(x)\) is the composition of the functions, also can be written as \(f(g(x))\). So, you plug g(x) in for the x in f(x).

OpenStudy (anonymous):

so it should be 4x^2+1

OpenStudy (anonymous):

When you substitute it in, don't forget to put parentheses around it. Also, don't forget the -3 :)

OpenStudy (anonymous):

thanks! last quesion where do i get the h for the second part

OpenStudy (anonymous):

You just use x+h, you don't need h to actually be anything. So just put (x+h) in instead of x, and then simplify it

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